C8h18 O2 Co2 H2o

How do you balance that? C8H18 + O2> CO2 + H2O? 3

First, the reaction is an irritation (you need to identify the nature of the reaction before balancing), so it must be balanced with trial and error:

C8H18 + O2> CO2 + H2O

1) You have 8 coals and on the right you have 1.

You need to multiply this 1 by 8 so that the sum is equal to 2 sides of the equation.

* C8H18 + O2> 8CO2 + H2O

2) As multiplication, the oxygen in the CO2 molecule increases. This molecule will not have 2 more, but 16.

3) Leaving oxygen at the end is what you accept the most because O2 on the left does not change any element other than oxygen.

4) You compare hydrogen the same way you saw before: you have 18 on the left and 2 on the right (multiply by 9 on the right).

* C8H18 + O2> 8CO2 + 9H2O

5) So far, the equation should look like this: C8H18 + O2> 8CO2 + 9H2O

Then, 25 cows on the right and only 2 on the left

You multiply O2 on the left by 12.5 and it is balanced.

* C8H18 + 12.5 O2> 8CO2 + 9H2O

PS: You have to put a number in front of each molecule, so 12.5 can be considered bad, you have to multiply the number by 2 in front of each molecule:

2C8H18 + 25 O2> 16CO2 + 18H2O

C8H18 + 25 / 2O2> 8CO2 + 9H2O

So we have:

8 coal

18 Hydrogen

25 Oxygen

Is trying

Any prime other than hydrogen or oxygen

It is offset by water molecules

For this reason

The amount of carbon in Prime is the same.

C8H18 + O2> 8CO2 + H2O

After hydrogen

C8H18 + O2> 8CO2 + 9H2O

For sure oxygen

C8H18 + 12.5O2> 8CO2 + 9H2O

Then everything is multiplied by 2 to get the number ent. Get

2C8H18 + 25O2> 16CO2 + 18H2O

C8H18 + 12.5 O2> 8 CO2 + 9 H2O

If it's a decimal, EHH !! 12.5 of OXàGENO

Okay let's see:

C8H18 + 25 / 2O2> 8CO2 + 9H2O

Thank you very much

C8h18 O2 Co2 H2o