E Mc2 Solve For C

Did you solve for C in E = MC2? 3

There is a question on my math test that says.

Solve for c, which means c = song.

It says e = mc2 and tells me to solve c. Does anyone have the answer?

E = mc2> Square root (E / M) = C

Well, that may not be the scene, but I'll explain. He asks you to get C himself. So first divide both sides by pt. Now you have completed by dividing E by m = c square. Now take both sides and root them and you get the square root of E divided by M = C.

For example, create a scene with a short walk.

And ends after Mc2 C. in.

E Mc2 Solve For C

y = 7 (15 + x) x value
Since E = M x C x C, divide both sides by M. All that's left is E / M = C2, take the square root on both sides, which then becomes C alone.
C = square root of E / M (E divided by M)
Without context, the answer is difficult to find, but the equation relates to the energy produced by the atom. C at e = m (c * c) is the Sd of light, which is 299,792,458 meters per second. So you would be right at 299,792,458 m / s.
Divide both sides by m so that only one side gets c 2. Now make a square root on both sides to remove the exponent.
Solving c means you rearrange the equation to read c = [expression], and the expression does not have cs.
As always, whatever operation you use must be applied to both sides of the equation.
e = mc²
Divide both sides of the equation by m.
e / m = c²
Take the square root on both sides
Âš (e / m) = c
Since when
E = MC 2
Divide both sides with step 1M.
C 2 = E / M
Step 2 Connect the square root on both sides.
C = Square (E / M)
What helps, for example.
Isn't C permanent?
C sd is equal to light.
299 792 458 m / s or 3.00 x 10 6 or 3 million m / s
And even in a relationship, C doesn't change.
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