Integral Of Sec 3x

Second Integral 3x / Tan 4x? 3

 "Dry 3x / tin 4x dx

= ˆ "1 / [cos 3 x * sin 4 x / cos 4 x] dx

= Cos "cos x dx / sin 4 x dx

Let's go = sin x

du = cos x dx

Cos "cos x / sin 4 x dx = ˆÂ" du / u 4

= ˆ «u (4) You

= u (4 + 1) / (4 + 1)

= 1 / (3u 3)

Replace you with sin x.

= 1 / (3 sins 3 x) + c

= csc 3x / 3 + C

ˆ "(1 / cos 3 (x)) * (cos 4 (x) / sin 4 (x)) dx =

Cos "cos (x) / sin 4 (x) dx =

1 "1 / sin 4 (x) d (sin (x)) =

(1/3) * (1 / sin 3 (x)) + C

Section (x) / tanà  (x)

= Dry (x) stump (x)

= cscó (x) nurture (x)

«Csc³ (x) cradle (x) dx = csc³ (x) / 3 + C

Integral Of Sec 3x