Lattice Energy Of Cacl2

Have you calculated the power of Cacl2 network? 3

Calculate the network energy of Cacl2 by assuming sublimation heat Ca = 121 kJ / mol and “Hf Cacl2 = 795”.

First ionization approx = 589.5

The second ionization approx = 1145

Electron affiliation Cl = 349

The binding energy of cl2 is 242.7.

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This question is based on the cycle of birth.

What happened to RXN?

ca (s) + cl2 (g) ______ Cacl2 now deltaHf = 795 kj / mol

Total enthalpy of ionization = 589.5 + 1145 = 1734.5 kJ / mol

Sublimation enthalpy = 121 kj / mol

Total Binding Dissolution Enthalpy = 242.7 kJ / mol

We have two atoms of cl, so electron enthalpy n = 2 * (349) = 698 kJ / mol for two atoms, because electron enthalpy n = (relation of electrons)

So Heber was born with a bicycle.

Anthology of Formation = Anthology of Sublimation + Anthology of Ionization + Anthology of Bond Dissociation + Anthology of N + Anthology of Electronic Netting

795 = 1734.5 + 121 + 242.7698 + Network Anthology

Then lattice anthelmintic = 795 1400.2 = 2195.2 kJ / mol

Grid energy calculation

Lattice Energy Of Cacl2

Cacl2 network power.
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Are you going to calculate the energy of Cacl2 network?
Calculating the network energy of Cacl2 sublimation heat Ca = 121 kJ / mol and “Hf Cacl2 = 795
First ionization approx = 589.5
The second ionization approx = 1145
Electron affiliation Cl = 349
The binding energy of cl2 is 242.7.
I got all the information I needed ...
With 589.5 and 1145?